315 m²
<u><em>area of rec + area of rec + area of rec + area of triangle</em></u>
⇒ length + width + length + width + length + width + 1/2 * base * height
⇒ 19 * 6 + 9 * 9 + 18 * 5 + 1/2 * 12 * 5
⇒ 90 + 30 + 81 + 114
⇒ 315 m²
Answer: The answer is D.
Step-by-step explanation:
Answer:
Solution given:
South distance :base[b]=80milea
East distance :perpendicular [p]=35miles
Now
<S=?
we have
=24°
24° bearing should be taken from south airport to East airport.
(16)/(2)*4-(10)/(5)+6= 36
Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.