2 years ago

What is the solution set of {x | x < -3} ∩ {x | x > 5}?

Mathematics

1 answer:

solniwko [45]2 years ago

5 0

x <-3 includes the numbers-4, -5, -6..........

x> 5 includes the numbers 6, 7 , 8.....

here we have to find intersection of these two.

By intersection we mean the values of x that occur in both the sets,

here there is no number or value of x that occur in both the sets.

So answer is empty set

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Mariana [72]

Answer:

a=formula : Sum of all side

= 3+5+3

=11 ans

Step-by-step explanation:

formula is sum of all side

so add 3+5+3 ans =11

this is simple method

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2 years ago

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2 years ago

Simone told you that she placed a point on the number line that had an absolute value of 15. At what two numbers could she have

makvit [3.9K]

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2 years ago

Simplify. 1/cosθ + tan^2θ/cosθ • 1 + sinθ • sec^3θ • 1 • cos^3θ

olchik [2.2K]

Answer:

I'm guessing the answer is sec³θ

Step-by-step explanation:

I tried this problem and I got 1/cos³θ and clicked cos³θ, but that answer was incorrect. In my lesson, there were the options:

1. sec³θ

2. cos³θ

3. secθ

I didn't have options 1 + sinθ or 1 as answers. If sec³θ is not the correct answer, please correct me.

8 0

2 years ago

What are the factors to the equation 4x2-52x + 169 121? A 4(x-1)(x+12) B 4(x + 1)(x - 12) C. 4(x + 1)(x+12) D. 4(x-1)(x - 12)

Bingel [31]

The given equation is,

$4x^2-52x+169=121$

Simplifying the above equation,

$\begin{gathered} 4x^2-52x+169-121=0 \\ 4x^2-52x+48=0 \end{gathered}$ $\begin{gathered} 4x^2-13\times4x+4\times12=0 \\ 4(x^2-13x+12)=0 \\ 4(x^2-12x-1x+12\times1)=0 \\ 4(x(x-12)-1(x-12))=0 \\ 4(x-12)(x-1)=0 \end{gathered}$

Therefore, the factors of the given expression is 4(x-1)(x-12).

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3 months ago