The launch velocity of the marble launcher is 34.65 m/s
Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).
The time for landing can be calculated by the second equation of motion formula:
h = ut + 
g
Let u = 0
0.2 = 0×t + × 9.8 ×
= 
= 0.04
t = 0.2s
Now, the launch velocity of the marble launcher can be calculated by:
Speed = Distance / Time
Speed = 
Speed = 
Speed = 34.65 m/s
Therefore, the launch velocity of the marble launcher is 34.65 m/s
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Answer:
<h2>A.
6pF</h2>
Explanation:
If unknown capacitance C1, C2, C3 and C4 are connected in series to one another, their equivalent capacitance of the circuit will be expressed as shown
Given the capacitance's 3.0 pF, 2.0 pF, 5.0 pF and X pF connected in series to each other. If the equivalent capacitance of the circuit is 0.83 pF, then to get X, we will apply the formula above;
C₄ ≈ 6pF
Hence the value of the X capacitor is approximately 6pF
Answer: D. It is a SUSPENSION
Explanation:
SUSPENSION
This is a combination of two or more single substances. The properties of the components involved are not however changed or lost as is the case with compounds.
For this reason this mixture can be separated due to sedimentation or filtering.
After a few days, this occurs in the aqueous nickel sulfide because the solid nickel sulfide is separating from the water.
Answer:
Explanation:
When the craft was stationary , weight will be balanced by tension
T = mg
T = 7000 N
A)
when the craft was being lowered to the seafloor
drag force will act in upper direction , so
T₁ + 1800 = mg
T₁ = mg - 1800
= 7000 - 1800
= 5200 N
52 X 10² N
B)
when the craft was being raised from the seafloor , Tension will act in downward direction
T₂ = mg+ 1800
T₂ = 7000 - 1800
= 8800N
