Answer:
a. Values are - (1) 3,1,-1,1/2 (2) 2,1,-1,-1/2 (3) 3,0,0,1/2 (4) 4,3,3,-1/2
(5) 3,2,2,1/2
b. Order be- I > Sn > Xe
Explanation:
a.
Valid quantum numbers are -
'l' value should be less than 'n' value and 'ml' value should be '-l' to 'l'
'ml' value should not more than 'l' or 'n'.
Values are -
3,1,-1,1/2
2,1,-1,-1/2
3,0,0,1/2
4,3,3,-1/2
3,2,2,1/2
b.
Given that-
I [Kr]4d¹⁰5s²5p⁵
Sn [Kr]4d¹⁰5s²5p²
Xe [Kr]4d¹⁰5s²5p⁶
Order be-
I > Sn > Xe
Xe is least because it is completely filled outer shell (5s²5p⁶
Answer:
atoms of 40K
Explanation:
You can use the molecular mass and the Avogadro´s number, in the following formula:
where 
is the sample mass, 
is the molecular mass of the KCl and IA(40K) is the isotopic abundance of 40K.
Now replacing the values, you can find:
2Ca3(PO4)2 + 6SiO2 + 10C ---> P4 + 6CaSiO3 + 10CO
1 mole of Ca3(PO4)2 = 310g
1 mole of P4 = 124g
according to the reaction:
2*310g Ca3(PO4)2----------------124g P4
x g Ca3(PO4)2 ------------------------ 30g P4
x = 150g Ca3(PO4)2
so, your answer is good
Answer:
2.1 moles of water formed.
Explanation:
Given data:
Moles of water formed = ?
Moles of Ni(OH) = 4.20 mol
Solution:
Chemical equation:
2Ni(OH) → Ni₂O + H₂O
Now we will compare the moles of Ni(OH) with water.
Ni(OH) : H₂O
2 : 1
4.20 : 1/2×4.20 = 2.1 mol
2.1 moles of water formed.
