The denominator can't be equal to 0.
The domain is all numbers except -3 and 3.
Answer:
account for the majority of O-rings produced, namely Nitrile, EPDM and ... For the most current information, contact the O-Ring Division. ... O-ring resulting in “nibbling” (see Zatkoff Product catalog, ... 72 0,23. 30 0,25. 89 0,25. 47 0,25. 07 0,25. 64 0,25. 24 0,25. 82 0,30. 42 0,30. 99 0, ... JASO-1016 ... R12,5-591 ... R26,5-605.
Step-by-step explanation:
Answer:
angles of the triangle are equal 180
so 42+82=124
180-124=56
so the answer is 56
Step-by-step explanation:
<h2 /><h2>
<u>Question</u><u>:</u></h2>
<u>find the height of the cylinder whose volume is 1.54 cubic m and radius of the base is 70 cm</u>
Required diagram :
<h3>Solution :</h3>
For a cylinder having a radius r and a height h ;
Volume Of Cylinder :
Here , the radius of the cylinder is given as 70 cm and the volume is 1.54 m³ .
Converting ;
- 1 m³ = 1 × 10⁶ cm³ .
- > 1.54 × 10⁶ cm³ .
- > 1540000 cm ³.
- > π r² h = 1540000
- > 22/7 × 70 × 70 × h = 1540000
- > 22 × 10 × 70 h = 1540000
- > 15400 h = 1540000
- > h = 100 cm = 1 m.
<u>The</u><u> </u><u>height</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>cylinder</u><u> </u><u>is</u><u> </u><u>100cm</u><u>.</u><u>=</u><u>1m</u><u>.</u>
Answer:
(A) AA Similarity Theorem
Step-by-step explanation:
Given: AB ∥ DE
To Prove:
Given Triangle ABC with Line DE drawn inside of the triangle and parallel to side AB. The line DE forms a new triangle DCE.
Because AB∥DE and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines.
Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
We can state ∠C ≅ ∠C using the reflexive property.
Therefore, by the AA similarity theorem.
Remark: In the diagram, we can see that the two triangles share Angle C and have two equal angles at E and B. Therefore, they are similar by the Angle-Angle Similarity Theorem.