The probability that a student is taking both math and computer science is option B) 11%.
<u>Step-by-step explanation:</u>
Given that,
The probability that a student is taking math alone = 23%.
The probability that a student is taking computer science alone = 45%.
The probability that a student is taking math or computer science = 58%.
<u>To find the probability that a student is taking both math and computer science :</u>
We use the formula P(A∪B) = P(A) + P(B) - P(A∩B)
Here,
P(math ∪ computer) = P(math) + P(computer) + P(math or computer)
⇒ 23% + 45% - 58%
⇒ 10%
Therefore, 10% is the probability that a student is taking both math and computer science.
We can choose option B) 11% as the correct answer since it is nearest to the 10%.