For B, it is because water is a really good conductor of electricity, so the electrician will get shocked
Answer:
A nuclear winter is a climatic phenomenon that would follow the detonation of several atomic bombs in the event that a nuclear war broke out. These bombs would cause firestorms that would raise smoke, dust and particles into the atmosphere that would end up in the stratosphere and eventually spread throughout the globe.
Explanation:
That idea is far fetched, because even though those same particles would absorb sunlight, it would raise the temperature in the stratosphere and cause a decrease in temperature in the Earth's layer. Unable to seep the sun's rays, many plant species would die and this would affect the entire food chain.
In addition, that temperature rise in the stratosphere would destroy part of the ozone layer, causing greater exposure to ultraviolet rays. This would end up affecting health and further damaging plant species.
The first thing you should know for this case is that work is defined as the product of force by the distance traveled in the direction of force.
We have then:
W = Fd
The distance varies, so we must integrate:
from 0 to 20:
W = ∫F (x) dx
W = ∫32xdx
W = 32∫xdx
W = 32 (x ^ 2/2) = (16) (20 ^ 2) = 6400 ft * lbs
answer:
6400 ft * lbs is work done pulling the rope up 20 ft
m = mass held by mr. Z above his head = 200 kg
g = acceleration due to gravity = 9.8 m/s²
F = force applied by mr. Z to hold the mass
Using equilibrium of force , force equation is given as
F = mg
F = (200) (9.8)
F = 1960 N
Since the mass is not moved,
d = displacement of the mass = 0 m
we know that , work done is given as
W = F d
inserting the values
W = (1960) (0)
W = 0 J
Answer:
q=1.7346×10⁻⁶C
Explanation:
Since the electric field is perpendicular to the bottom and top of the cube,the total flux is equals the flux over the top of surface plus the flex over the lower surface
Ф(total)=Ф₃₀₀+Ф₂₃₀
But the flux is given by Ф=E.A=EACos(θ) where θ is the angle between Area vector and electric field
So
Ф(total)=E₃₀₀A Cos(180)+E₂₃₀ACos(0)
Ф(total)=A(E₃₀₀ - E₂₃₀)
The total flux is given by Gauss Law as:
Ф(total)=q/ε₀
q=ε₀Ф(total)
q=ε₀(A(E₃₀₀ - E₂₃₀))
Substitute the given values
q=(8.85×10⁻¹²){(70²)(100 - 60)}
q=1.7346×10⁻⁶C