Metals is found on the left side of the table and the nonmetals is on the top right.
Answer:
a.
1. NO2(g): Reactant.
2. CO(g): Reactant.
3. NO3(g): Intermediate.
4. CO2(g): Product.
5. NO(g): Product.
b. See attached picture.
Explanation:
Hello,
a. In this case, given the reactions, we can identify each species as:
1. NO2(g): Reactant because it remains at the left side in the overall reaction.
2. CO(g): Reactant because it remains at the left side in the overall reaction.
3. NO3(g): Intermediate because it is a product in the step 1 and a reactant in step 2, for that reason it is not present in the overall reaction.
4. CO2(g): Product because it remains at the right side in the overall reaction.
5. NO(g): Product because it remains at the right side in the overall reaction.
b. In this case, given that the first step is slow and endothermic, it has a high activation energy and the products will have more energy than the reactants, for that reason the final energy is above the initial point. Moreover, since the second step is fast and exothermic, it has a low activation energy and the products will have less energy than the reactants, for that reason, the reaction coordinate diagram is shown on the attached file.
Regards.
If there are 0.2 M solutions of both acid and base, the concentrations of hydrogen and hydroxide ions will be equal at equivalence point.
The reaction of sulfuric acid and a basic solution BOH occurs as follows;
H2SO4(aq) + 2BOH(aq) -----> B2SO4(aq) + 2H2O(l)
In the question, we are told that that both the solution of the sulfuric acid and the basic solution are 0.2 M.
The point where all the hydrogen and hydroxide ions have reacted according to the stoichiometry of the reaction. If there is really equimolar amounts of acid and base, the concentration of hydrogen and hydroxide ions will be equal at equivalence point.
Learn more: brainly.com/question/2192784
Answer:
Follows are the solution to the given question:
Explanation:
Dry Soil weight = solid soil weight =
solid soil volume =
saturated mass soil =
The weight of the soil after drainage is =
Water weight for soil saturation =
Water volume required for soil saturation =
Sample volume of water:
Soil water retained volume = (draining field weight - dry soil weight)
(Its saturated water volume is equal to the volume of voids)
Answer:
a) 0.115 g
Explanation:
The balanced reaction is:
CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)
To heat 55g of water, the energy in form of heat necessary can be calculated by:
Q = mcΔT
where Q is the heat, m is the mass, c is the specific heat (for water, c = 4.18 J/gºC), and ΔT is the variation of the temperature, which is 25ºC, so:
Q = 55x4.18x25
Q = 5747.5 J = 5.7475 kJ
So, for the reaction, 1 mol of CH₄ releases 802.3 kJ, so to release 5.7475 kJ will be necessary:
1 mol ---------------- 802.3 kJ
x ---------------- 5.7475 kJ
By a simple direct three rule:
802.3x = 5.7475
x = 7.164x10⁻³mol
The molar mass of CH₄ is : 12 (of C) + 4x1 (of H) = 16 g/mol
The mass is equal to the number of moles multiplied by molar mass, the:
m = 7.164x10⁻³x16
m = 0.115 g