5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ
essive crests is 4.0 m. The timing starts with the first crest and ends with the fourth. What is the speed of the wave? BBoldIItalicsUUnderlineBulleted listNumbered listSuperscriptSubscript
1 answer:
Answer:
v= 1.71 m/s
Explanation:
Given that
Distance between two successive crests = 4.0 m
λ = 4 m
T= 7 sec
T is the time between 3 waves.
3 waves = 7 sec
1 wave = 7 /3 sec
So t= 7/3 s
We know that frequency f
f= 1/t= 3/7 Hz
Lets take speed of the wave is v
v= f λ
f=frequency
λ=wavelength
v= 3/7 x 4 = 12 /7
v= 1.71 m/s
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Answer:
1.137278672 m/s
+5.9 cm or -5.9 cm
Explanation:
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m = Mass of object = 225 g
k = Spring constant = 74.5 N/m
Maximum speed is given by
The maximum speed of the object is 1.137278672 m/s
Velocity is at any instant is given by
The locations are +5.9 cm or -5.9 cm
Answer:
(c) As 'd' becomes doubled, energy decreases by the factor of 2
Explanation:
Energy stored in a parallel plate capacitor is given by:
As capacitor remains connected to the battery so V remains constant. As can be seen from (1) that energy is inversely proportional to the separation between the plates so as 'd' becomes doubled, energy decreases by the factor of 2.