Answer:
0.41
Explanation:
given,
mass of the car, m = 2290 Kg
initial speed = 10.5 m/s
mass of another car, M = 2780 Kg
distance moved = 2.80 m
coefficient of friction = ?
conservation of energy
m u = (M + m) V
2290 x 10.5 = (2290 + 2780) V
V = 4.74 m/s
using equation of motion
v² = u² + 2 a s
4.74² = 2 x a x 2.8
a = 4.02 m/s²
now using equation
a = μ g
4.02 = μ x 9.8
μ = 0.41
Answer:
The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.
(3) and (4) is correct option.
Explanation:
Given that,
Beat frequency f = 5.0 Hz
Frequency f'= 462 Hz
We need to calculate the possible frequencies for the A string of the other violinist
Using formula of frequency
...(I)
...(II)
Where, f= beat frequency
f₁ = frequency
Put the value in both equations
Hence, The possible frequencies for the A string of the other violinist is 467 Hz and 457 Hz.
Answer:
The force exerted on the is
Explanation:
From the question we are told that
The area is
The magnitude of charge placed on them is
The charge placed between the plate is
The electric field generated around the plate is mathematically represented as
Substituting values
The force exerted the charge is mathematically represented as
Substituting values
Answer:
You need to use charts or a calculator to get 56%
Explanation:
I thinks it’s 2...........