Answer:
To solve this, we need to recall that Work done W,
W = F x dₐ Eqn 1
where F is the gravitational field force and d is the distance travelled by the earth.
But F = −(mMG)r/|r|³ Eqn 2
then, W = −∫ (mMG)r/|r|³ x dₐ
Integrating this expression gives us
W = -4mMG ((1/d1) -(1/d2))
m = 5.971024 kg, M = 1.991030 kg G = 6.67 ✕ 10⁻¹¹ N·m²/kg²
d2 = 1.52x10¹¹m, d1 = 1.47x10¹¹m make the units in S.I units and similar
Substituting these value in to the eqn above gives
Now , W = 1.77 x 10³²J (2 Decimal Places)