Answer:
non of the above thanks
don't ask me again please
Answer:
P(C4) = 0.0711
Step-by-step explanation:
consider the first draw = 15/23 since it cannot be a blue ball
The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn
the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn
therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41
Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41
P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )
= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711
Answer:
251
Step-by-step explanation:
Answer:
The Probability of the pebble landing on red = 1/3
The Probability of the pebble landing on blue = 1/6
The Probability of the pebble landing on white = 1/2
Total sum of probability = 1/3 + 1/6 + 1/2 = 1
The probability that the first pebble lands on blue and second pebble lands on red is:
1/6 * 1/3
= 1/18
Step-by-step explanation:
Red, Red = 1/3 * 1/3
Red, Blue = 1/3 * 1/6
Red, white = 1/3 * 1/2
Blue, Blue = 1/6 * 1/6
Blue, Red = 1/6 * 1/3
Blue, white = 1/6 * 1/2
White, White = 1/2 * 1/2
White, Red = 1/2 * 1/3
White, Blue = 1/2 * 1/6
Answer:
Look at pics.
Step-by-step explanation:
Hope this helps!
