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2 years ago

X=18+9/2y help Me please

Mathematics

1 answer:

Nana76 [90]2 years ago

4 0

Answer:

x = 18 + 9y/2

x-18 = 9y/2

(x-18)x2=9y

2(x-18)=9y

2(x-18) / 9 = y

y= 2(x-18)/9

Step-by-step explanation:

Simplify 9/2y to 9y/2

Then Subtract 18 from both sides

Now Multiply both sides by 2

Then Regroup the terms

now divide both sides by 9

Then you will Switch sides

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Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

Step-by-step explanation:

Given

$f(x)=x^3-12x^2+35x-24$

$f(8) = 0$

Required

Find all zeros of the f(x)

If $f(8) = 0$ then:

$x = 8$

And $x - 8$ is a factor

Divide f(x) by x - 8

$\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}$

Expand the numerator

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}$

Rewrite as:

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}$

Expand

$\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}$

$\frac{f(x)}{x - 8} = (x - 1)(x - 3)$

Multiply both sides by x - 8

$f(x) = (x - 1)(x - 3)(x - 8)$

Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

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••••

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$y = 8 - 3x$

$y = 8 - 3 \times 0$

$y = 8$

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