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2 years ago

A dialysis unit requires 60000 mL of distilled water. How many gallons of water are needed? (1 gal = 4 qt)

Chemistry

2 answers:

stira [4]2 years ago

8 0

It is 16 gallons in 1 quart

stiks02 [169]2 years ago

7 0

Answer : The water needed are 15.85 gallons.

Explanation :

The conversion used for volume form milliliters to gallons are:

$1\text{ gallon}=3785.41mL$

or,

$1mL=\frac{1}{3785.41}\text{ gallon}$

As we are given that the volume of water 60000 mL. Now we have to calculate the volume of water in gallons.

As, $1mL=\frac{1}{3785.41}\text{ gallon}$

So, $60000mL=\frac{60000mL}{1mL}\times \frac{1}{3785.41}\text{ gallon}=15.85\text{ gallons}$

Therefore, the water needed are 15.85 gallons.

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Which change would increase the pressure exerted by a gas?

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Answer:

C - raising the temperature of a gas

Explanation:

as you raise temperature, kinetic energy rises, and so does pressure

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2 years ago

Which of the following gases will have the highest velocity at a given temperature?

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The velocity of the gas is inversely proportional to the square root of the molar mass of the gass. Heavier molecules tend to travel slow compared to light molecules. Among these, He has the lowest molar mass of 4 g/mol hence this element has the greatest velocity among all molecules given.

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2 years ago

Read 2 more answers

The volumetric analysis of mixture of gases is 30 percent oxygen, 40 percent nitrogen, 10 percent carbon dioxide, and 20 percent

SOVA2 [1]

Answer: $Q=234kJ/kg$

Explanation:

Hello,

In this case, the transferred heat to the mixture is given by the addition among each compound's specific enthalpies:

$Q=h_{O_2}+h_{N_2}+h_{CO_2}+h_{CH_4}$

Now, each specific enthalpy is given by the following equation:

$h_i=\int\limits^{T_2}_{T_1} {Cp_i(T)} \, dT$

As long as there is a large difference between the initial and the final temperature. In such a way, the shown below polynomial for the Cp which is given kJ/kmol*K is considered and subsequently integrated:

$Cp(T)=a+bT+cT^2+dT^3\\\int\limits^{T_2}_{T_1} {Cp(T)} \, dT =a(T_2-T_1)+\frac{b}{2}(T_2^2-T_1^2)+\frac{c}{3}(T_2^3-T_1^3)+\frac{d}{4}(T_2^4-T_1^4)$

Now, the specific enthalpy is computed for each component considering the temperatures in Kelvin:

$h_{O_2}=25.48(473.15K-293.15K)+\frac{1.520x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{-0.7155x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{1.312x10^{-9}}{4}(473.15K^4-293.15K^4)=5456.2kJ/kmol$

$h_{N_2}=28.9(473.15K-293.15K)+\frac{-0.1571x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{0.8081x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{-2.873x10^{-9}}{4}(473.15K^4-293.15K^4)=5280.4kJ/kmol\\$

$h_{CO_2}=22.26(473.15K-293.15K)+\frac{5.981x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{-3.501x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{7.469x10^{-9}}{4}(473.15K^4-293.15K^4)=7269.4kJ/kmol\\$

$h_{CH_4}=19.89(473.15K-293.15K)+\frac{5.024x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{1.269x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{-11.01x10^{-9}}{4}(473.15K^4-293.15K^4)=7269kJ/kmol\\$

Now, we convert them per unit of mass as:

$h_{O_2}=5456.2kJ/kmol*\frac{1kmol}{32kg}=170.5kJ/kg\\h_{N_2}=5280.4kJ/kmol*\frac{1kmol}{28kg}=188.6kJ/kg\\h_{CO_2}=7269.4kJ/kmol*\frac{1kmol}{44kg}=165.2kJ/kg\\h_{CH_4}=7269kJ/kmol*\frac{1kmol}{16kg}=454.3kJ/kg$

Finally, by considering the volumetric percentages, we compute the heat transferred to mixture:

$Q=0.3*170.5kJ/kg+0.4*188.6kJ/kg+0.1*165.2kJ/kg+0.2*454.3kJ/kg\\Q=234kJ/kg$

Best regards.

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2 years ago

The path of an electron inside an element is called

Feliz [49]

Answer:

orbit

Explanation:

Though electrons can be represented simply as circling the nucleus in rings, in reality, electrons move along paths that are much more complicated. These paths are called atomic orbitals, or subshells. ... Each orbital can hold only two electrons. Electrons that occur together in an orbital are called an electron pair.

hope it helps !

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2 years ago

A rectangular box has a length of 12 cm, a width of 20 cm, and

Zepler [3.9K]

Answer: a. 1,200 mL

Explanation:

20 x 12 x 5 = 1,200

(L x W x H)

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2 years ago