Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
Answer:
f(-2) = -3
Explanation:
Not sure if those last couple numbers are answer choices, but I'm going to infer that they might be.
Twenty four over the quantity of 3 x minus two in standard form is:
f(x) = <span>24<span>3x−2</span></span>
Since the number in the ( ) = x, plug in for x using f(-2)
<span>24<span>3∗<span>(−2)</span>−2</span></span>
P E {M D} {A S} for where to solve first
Multiply the 3 and (-2):
<span>24<span>−6−2</span></span>
Add -6 and -2:
<span>24<span>−8</span></span>
Divide the rest:
f(-2) = -3
The surfaces are the faces of the prism. The vertices are the points of the prism, where three sides intersect. You can also call them corners. To find the volume, you multiply length and width and height.
X, x + 2, x + 4 cause if you add 1 it becomes even so add 2 everytime to keep it odd