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2 years ago

What is the correct name for the compound p4o6?

Chemistry

1 answer:

Arturiano [62]2 years ago

3 0

Tetraphosphorus Hexoxide

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Working with one sample at a time, add water to the glass one tablespoon at a time. Water should soak the sample from the bottom

Vedmedyk [2.9K]

Answer:

This is confusing

but if you still need help, you can search it online

Explanation:

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2 years ago

Read 2 more answers

How many moles are in 8.32 times 1024 molecules of CO2

Svetradugi [14.3K]

Answer:

13.8 mol CO₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

8.32 × 10²⁴ molecules CO₂

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

$8.32 \cdot 10^{24} \ molecules \ CO_2(\frac{1 \ mol \ CO_2}{6.022 \cdot 10^{23} \ molecules \ CO_2} )$ = 13.816 mol CO₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

13.816 mol CO₂ ≈ 13.8 mol CO₂

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2 years ago

Please help me with this homework

KengaRu [80]

Answer:

The answer is C density.

8 0

2 years ago

CAN SOMEONE HELP ME PLZ AND THANKS WILL MARK U AS BRAINLIEST

jekas [21]

Explanation:

2. $2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O$

First, we need to find the number of moles of $CO_2$ at 300K and 1.5 atm using the ideal gas law:

$n= \dfrac{PV}{RT}= \dfrac{(1.5\:\text {atm})(33\:L)}{(0.082\:\text{L-atm/mol-K})(300K)}$

$=2.0\:\text{mol}\:CO_2$

Now use the molar ratios to find the number of moles of ethane to produce this much $CO_2$ .

$2.0\:\text{mol}\:CO_2 \times \left(\dfrac{2\:\text{mol}\:C_2H_6}{4\:\text{mol}\:CO_2}\right)$

$=1.0\:\text{mol}\:C_2H_6$

Finally, convert this amount to grams using its molar mass:

$1.0\:\text {mol}\:C_2H_6 \times \left(\dfrac{30.07\:\text g\:C_2H_6}{1\:\text{mol}\:C_2H_6} \right)$

$=30.1\:g\:C_2H_6$

3. $3Zn + 2H_3PO_4 \rightarrow 3H_2 + Zn_3(PO_4)_2$

Convert 75 g Zn into moles:

$75\:\text g\:Zn \times \left(\dfrac{65.38\:\text g\:Zn}{1\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:Zn$

Then use the molar ratios to find the amount of H2 produced.

$1.1\:\text{mol}\:Zn \times \left(\dfrac{3\:\text{mol}\:H_2}{3\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:H_2$

Now use the ideal gas law $PV=nRT$ to find the volume of H2 produced at 23°C and 4 atm:

$V= \dfrac{nRT}{P}= \dfrac{(1.1\:\text{mol}\:H_2)(0.082\:\text{L-atm/mol-K})(296K)}{4\:\text{atm}}$

$=8.9\:\text L\:H_2$

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2 years ago

What are two physical changes that could occur with a piece of paper?

Mekhanik [1.2K]

The paper being torn in half or folding it

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2 years ago