X+23=-22
-23 -23
x=-45
a+(-1.3)=-4.5
or
a-1.3+-4.5
+1.3 +1.3
a=3.2
Answer:
1000(1/20000) +
300(2/20000) +
10(20/20000) +
=
1800/20000 = .09
Step-by-step explanation:
Each ticket purchased is expected to win 9 cents
Each ticket purchased cost 75 cents
If you interpret expected winnings per ticket to include the cost then each ticket is expected to lose 66 cents.
If the ratio is 90:3 and there are 4 groups of 3 in 12, then the ratio would then be 450:12, leaving you with 450 as the answer. Hope I helped
Answer:
0.35% of students from this school earn scores that satisfy the admission requirement.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.
This means that
The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?
The proportion is 1 subtracted by the pvalue of Z when X = 2294. So
has a pvalue of 0.9965
1 - 0.9965 = 0.0035
0.0035*100% = 0.35%
0.35% of students from this school earn scores that satisfy the admission requirement.