Explanation:
The given reaction is as follows.
Value of equilibrium constant is given as 
= 4.3 \times 10^{6}[/tex].
Concentration of given species is ![[SO_2]](https://tex.z-dn.net/?f=%5BSO_2%5D)
= 0.010 M; ![[SO_3]](https://tex.z-dn.net/?f=%5BSO_3%5D)
= 10.M; ![[O_2]](https://tex.z-dn.net/?f=%5BO_2%5D)
= 0.010 M.
Formula for experimental value of equilibrium constant (Q) is as follows.
Q = ![\frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BSO_%7B3%7D%5D%5E%7B2%7D%7D%7B%5BSO_%7B2%7D%5D%5E%7B2%7D%5BO_%7B2%7D%5D%7D)
Putting the given concentration as follows.
Q =
Q = 
Q = 
It is known that when Q > 
, then reaction moves in the backward direction.
When Q < , then reaction moves in the forward direction.
When Q = , then reaction is at equilibrium.
As, for the given reaction Q > then it means reaction moves in the backward direction.
Thus, we can conclude that the reaction is moving in the backward direction, that is, right to left to reach the equilibrium.
I think maybe reptiles bu i could be wrong. :)
Answer: 400K
Explanation:
Given that,
Original volume of balloon V1 = 3.0L
Original temperature of balloonT1 = 27°C
Convert the temperature in Celsius to Kelvin
(27°C + 273 = 300K)
New volume of balloon V2 = 4.0L
New temperature of balloon T2 = ?
Since volume and temperature are given while pressure is constant, apply the formula for Charle's law
V1/T1 = V2/T2
3.0L/300K = 4.0L/T2
To get the value of T2, cross multiply
3.0L x T2 = 4.0L x 300K
3.0LT2 = 1200LK
Divide both sides by 3.0L
3.0LT2/3.0L = 1200LK/3.0L
T2 = 400K
Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.
Answer:
Maybe A)
Explanation:
Can you make me the Brainliest answer ?
