Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
Answer:
the first number is 2, the second number is 9 :)
Step-by-step explanation:
brainliest? :)
I need a picture or something to answer this question
Answer:
hopes it's helps
Step-by-step explanation:
I got 20 blocks for my answer
