Answer:
The answer is 288
Step-by-step explanation:
I did the assinment
Answer:
The given line segment has a midpoint at (−1, −2).
On a coordinate plane, a line goes through (negative 5, negative 3), (negative 1, negative 2), and (3, negative 1).
What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?
y = −4x − 4
y = −4x − 6
y = One-fourthx – 4
y = One-fourthx – 6
y = Three-halvesx + 1
B) y = 4x
X| * |Y|
2|2*4|8 |
3|3*4|12|
4|4*4|16|
5|5*4|20|
Answer:
i don't get the question ...
Step-by-step explanation:
Answer:
Step-by-step explanation:
- x + y + z = -3 --> (1)
- 3y - z = 4 --> (2)
- 2x - y - 2z = -5 --> (3)
<u>Add up (1) and (2)</u>
- x + 3y + y + z - z = -3 + 4 ⇒ x + 4y = 1 --> (4)
<u>Double (2) and subtract from (3)</u>
- 2x - y - 2z - 2(3y - z) = -5 - 2(4) ⇒ 2x - y - 2z - 6y + 2z = -5 - 8
- 2x - 7y = -13 --> (5)
<u>Double (4) and subtract (5)</u>
- 2(x + 4y) - 2x + 7y = 2 + 13 ⇒ 2x + 8y - 2x + 7y = 15 ⇒ 15y = 15 ⇒ y = 1
<u>Finding x</u>
- x + 4(1) = 1 ⇒ x = 1 - 4 ⇒ x = -3
<u>Finding z</u>
<u>So the answer is: </u>
