P: 152 (as long as the one is a square like i’m viewing it as, i can’t really tell) and then a: 110 (forgive me if i’m wrong i’m rusty on this )
Let denote the rocket's position, velocity, and acceleration vectors at time .
We're given its initial position
and velocity
Immediately after launch, the rocket is subject to gravity, so its acceleration is
where .
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,
(the integral of 0 is a constant, but it ultimately doesn't matter in this case)
and
b. The rocket stays in the air for as long as it takes until , where is the -component of the position vector.
The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):
c. The rocket reaches its maximum height when its vertical velocity (the -component) is 0, at which point we have
A tell me out of 9 13 23
What is the smallest number or the number closest to 0
Answer:
839393
Step-by-step explanation:
Answer:
B = -0.03t + 0.24
Step-by-step explanation:
Given: battery is at 24% when Logan leaves the house; it loses 3% per hour.
"T" is a placeholder for every hour. In one hour, the phone will be at 21%.