Answer:
Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that 
and also 
.
In order to prove that ∆ABC 
∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:
9514 1404 393
Answer:
D. 61 mi/h
Step-by-step explanation:
The travel time is 16:52 -8:13 = 8:39 hours, or 8.65 hours. Then the speed is ...
speed = distance/time = 527.65 mi/(8.65 h) = 61 mi/h
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<em>Additional comment</em>
It is often convenient to use "military" or "24-hour" time for calculations of time periods that extend over noon or midnight. For this purpose, 12 gets added to the hour number in the afternoon (pm). Of course, 39 minutes is 39/60 hours. That is found to be 0.65 hours by performing the division of 39 by 60.
Answer:
Step-by-step explanation:
Answer:
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Step-by-step explanation:
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is 
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is 
. Thus, there are only 35 ways to distribute the blackboards in this case.
