Answer:
sorry if wrong put b as the answer
y is -2/53
Step-by-step explanation:
- Step 1: Given equation is y = 2/5x-3 and x = -10. Substitute value of x to find the solution.
⇒ y = 2/(5 × -10 - 3) = 2/-53 = -2/53
We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:
The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:
![CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack%20x-Z_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%2Cx%2BZ_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%5Crbrack)
Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:
![CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack30.0-Z_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%2C30.0%2BZ_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%5Crbrack)
Where (from tables):
Finally, the interval at 98% confidence level is:
23. J
7,220 kids drink zero.
14,060 kids drink one
5,700 kids drink two
(multiply the total amount of kids by the percent (convert percent to decimal))
When added together, you get 26,980.
24. C
5,700 kids drink two
2,660 kids drink three
1,140 kids drink four
7,220 kids drink five or more
When added together, you get 16,720 kids.
Next set up a proportion.
38,000 total 30 total kids
------------------ = --------------------
16,720 kids x
For 38,000 to get to 30, you have to divide 38,000 by 1,266.67.
This means that you also have to divide 16,720 by 1,266.67.
This gets you 13.
Answer:
Yes, you can conclude that ΔJKL ≅ XYZ.
Step-by-step explanation:
I forget how to describe it in geometric terms but, if you read the similarity statement again, and follow each angle, you'll notice that the shapes match, and they correspond to each other, it would be different if it said something like ΔLKJ ≅ XYZ because it does not match.
If you're looking for a specific reason, we'd say that they're congruent because of SAS (Side-Angle-Side)
If this still confuses you, hit me up.
