Answer:
16.05 amu
Explanation:
12.011 rounds to about 12.01 and 1.008 rounds to about 1.01 so when adding you'd do [12.01 + (1.01×4)]= 16.05
All of the questions here are pertaining to the colligative properties of a solution and the preparation of solutions. Maybe, it would be best if you understand the equations to be used in order to answer these questions.<span>
Freezing point depression or Boiling point elevation:
</span><span>ΔT = -K (m) (i)
</span>ΔT is the change in the freezing point or the boiling point not the freezing point/boiling point. Therefore, it should be added to the original value of the property of the solvent.
<span>
K is a constant called the molal freezing point depression constant and for the boiling point is the boiling point elevation constant. It is a property of the solvent.
</span><span>
m is the concentration of the solute in the solvent in terms of molality or kg solute/kg solvent.
</span><span>
i is the vant hoff factor which will represent the number of ions which the solute dissociates when in solution.</span>
Answer:
the catalyst is for activation energy
Explanation:
It is known that formula for area of a sphere is as follows.
A = 
= 
= 3.14 
= (27 + 273.15) K = 300.15 K
T = (77 + 273.15) K = 350.15 K
Formula to calculate the net charge is as follows.
Q = 
where, e = emissivity = 0.85
s = stefan-boltzmann constant = 
A = surface area
Hence, putting the given values into the above formula as follows.
Q =
= 
= 1046.63 W
Therefore, we can conclude that the net flow of energy transferred to the environment in 1 second is 1046.63 W.
