Answer:
20m/s = 72km/h
Explanation:
change 2km=2000m
The speed of the train is
v.t=S <=> v=S/t=2000/100=20 m/s
Answer:
A.) r = 2t
B.) V = 33.5t^3
Explanation:
Given that a spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 2 cm/s
A) Express the radius (r) of the balloon as a function of the time (t).
Since the rate = 2 cm/s that is,
Rate = radius/ time
Therefore,
2 = r/t
Make r the subject of formula
r = 2t
(B) If V is the volume of the balloon as a function of the radius, find V or and interpret it.
Let assume that the balloon is spherical. Volume of a sphere is;
V = 4/3πr^3
Substitute r = 2t into the formula
V = 4/3π(2t)^3
V = 4/3π × 8t^3
V = 32/3 × πt^3
V = 33.5t^3
Answer
Mass m = 78 kg
Vertical height in each stage h = 11 m
(a).
Initial speed u = 0
Final speed v = 1.1 m / s
a = 0.055 m/s²
Work done
(b).Work done
W_b = 78× 9.8× 11
c)
Work done
Where V = final speed
= 0
v = 1.1 m / s
for deceleration a = -0.055 m/s²
now,
W_c = 545.75 × 11
Answer:
it will get slower and eventually she will stop jumping because there isnt enough force on the gravity causing her to go up and down
Explanation:
!!
