Bodies in space traveled in circles.
The planets revolved around the Earth.
Note that
1 J = 0.239 cal
By definition,
Work = Force x Distance
Therefore work done is
W = (1 N)*(2000 m) = 2000 J
In calories,
W = (2000 J)*(0.239 cal/J) = 478 cal
Answer: 478 calories
Answer:
The speed of the roller coaster at this point is 18.74 m/s.
Explanation:
Given that,
Weight of the student, W = 655 kg
Weight of the roller coaster, 
Radius of the roller coaster, r = 18 m
At the bottom of the loop, the weight of the roller coaster us given by :
If m is the mass of the roller coaster,
m = 66.83 kg
So,
v = 18.74 m/s
So, the speed of the roller coaster at this point is 18.74 m/s. Hence, this is the required solution.
Answer:
Explanation:
Amount of heat required can be found from the following relation
Q = mcΔT
m is mass of the body , c is specific heat and ΔTis rise in temperature .
Here m = 300 kg
c = 3350 J /kg k
ΔT = 30 - 25
= 5 °C
Putting the values in the expression above
Q = 300 x 3350 x 5
= 5025000 J
Rate at which energy is absorbed = 1200 J /s
Time required
= 5025000 / 1200
= 4187.5 S
= 69.8 minute
= 1 hour 9.8 mimutes.
Answer:
8.87 gallons of kerosene
Explanation:
Step 1: Given and required data
- Energy to travel by plane per passenger trip: 1,260 MJ/passenger trip
- Energy per gallon of kerosene: 142 MJ/gal
Step 2: Calculate how many gallons of kerosene it takes to make the trip by plane
We can calculate the amount of kerosene required by combining the factor provided in Step 1.
1 gal/142 MJ × 1,260 MJ/passenger trip = 8.87 gal/passenger trip
8.87 gallons of kerosene are required to make the trip by plane.
