Round each number to the nearest whole number. What is the best estimate for the answer to 276.37 – 67.81? A. 209 B. 208.6
2 answers:
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Answer:
The bulbs should be replaced each 1436.9 hours.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?
This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.
So it is X when Z = -2.33.
The bulbs should be replaced each 1436.9 hours.
Answer:
a)
Speed at Equator = 463.97 meters per second
Centripetal Acceleration at Equator = meters per second squared
b)
Speed at 30 degrees north of equator = 401.79 meters per second
Centripetal Acceleration at 30 degrees north of equator = meters per second squared
Step-by-step explanation:
The formula is:
Where
v is speed
R is radius
T is time
and another formula for centripetal acceleration:
Now,
a)
at equator, the radius is radius of earth (given), time in seconds is
T = 24 * 60 * 60 = 86,400
THus,
Speed at Equator = 463.97 meters per second
Centripetal Acceleration:
Centripetal Acceleration at Equator = meters per second squared
b)
At 30.0° north of the equator:
Now,
Speed =
Speed at 30 degrees north of equator = 401.79 meters per second
Centripetal Acceleration:
Centripetal Acceleration at 30 degrees north of equator = meters per second squared