What is the vertex of the equation, y= -3x^2+2x-7?
2 answers:
A
Given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
The x-coordinate of the vertex is
= -
y = - 3x² + 2x - 7 is in standard form
with a = - 3, b = 2 and c = - 7, hence
= - =
Substitute this value into the equation for y-coordinate
y = - 3 ()² + 2 ( ) - 7
= - + - = -
vertex = ( , - ) → A
1) with this formula you can calculate the value of x , x = -b/2a
2) substitute the values x = -(2)/2(-3) = 2/6 = 1/3
3) substitute the value of x in the function
y= -(3)(1/3)^2+(2*1/3)-7 = -20/ 3, therefore , the correct option is A
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