The acceleration and distance is related to the following expression:
y=v0*t + a*t^2/2 ; v0=0
y=44.1*100/2 = 2205m
hence, the speed will be
v=0 + a*t = 441m/s
from that height it will just be subjected to the gravitational acceleration
0=v_acc^2 -2g*y_free
y_free = v_acc^2/2g = 9922.5m
<span>y_max = y_acc+y_free = 441+9922.5 =10363.5m</span>
Simply, apply the formula
and insert the values of m = mass, v = velocity and E = Energy.
The result will be
, m = 1 kg
When you double capacitance and inductance, the new resonance frequency becomes f/2.
The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.
It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.
Xc = Xl
which gives the value for resonance frequency:
where;
f is the resonance frequency
L is the inductance
C is the capacitance
When you double capacitance and inductance, the new resonance frequency becomes;
Thus from above,
When you double capacitance and inductance, the new resonance frequency becomes f/2.
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The time taken by the pulse to travel from one support to the other is 0.208 s.
<h3>Given:</h3>
The mass of the cord is m = 0.65 kg.
The distance between the supports is, d = 8.0 m.
The tension in the cord is T = 120 N.
The time taken by the pulse to travel from one support to the other is given as,
Here, v is the linear velocity of a pulse. Its value is,
Then,
Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.
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To solve the problem it is necessary to apply the concepts related to Byle's Law and Avogadro's Law.
The ideal gas equation would help us find the final solution to the problem, defined by
Where,
T= Temperature of the gas
R = Universal as constant
n = number of moles
V = Volume
P = Pressure
For our case we have that the mass of Zn is 2.2g in moles would be
[/tex]
We know that 1 mole of hydrogen gas is proceed by 1 mole of zinc and the result is , then Hydrogen can produce the same quantity,
Applying the previous equation we have that
Therefore the volume of hydrogen gas is collected is 0.829L