(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
Answer:
a = 10
b = 6.633
Step-by-step explanation:
x²+ y²= 125.
In this equation, the value of x and y represent the coordinates of x and y respectively of point on which the circle passes.
<u>(a,5)</u>
x²+ y²= 125
a² + 5² = 125
a² + 25 = 125
a² = 125-25
a² = 100
a = √100 = 10
(9,b)
x²+ y²= 125
9² + b² = 125
b² 125 - 81
b² = 44
b = √44 = 6.633
It is the first one,
........ 20. 24
256a. b
