38773 - 14056 = 24717
24717 + 14056 = 38773
<u>Answer:</u>
The grade you make on your exam varies directly with the number of correct answers. The constant of variation is 5
<u>Solution:</u>
Given, The grade you make on your exam varies directly with the number of correct answers you get on the exam.
Answering 15 questions correctly will give you a grade of 75 what is the.
We have to find what is the Constant of variation.
Now, according to the given information, grade number of correct answer
Then, grade = c x number of correct answers, where c is constant of variation.
Now, substitute grade = 75 and number of correct answers = 15
Hence, the constant of variation is 5
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
Answer:
D = { -4,-1,3,5,6}
Step-by-step explanation:
The domain is the x values or the inputs
D = { 3,6,-1,5,-4}
We normally put them in order from smallest to largest
D = { -4,-1,3,5,6}
Answer:
(a) 0.2061
(b) 0.2514
(c) 0
Step-by-step explanation:
Let <em>X</em> denote the heights of women in the USA.
It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.
(a)
Compute the probability that the sample mean is greater than 63 inches as follows:
Thus, the probability that the sample mean is greater than 63 inches is 0.2061.
(b)
Compute the probability that a randomly selected woman is taller than 66 inches as follows:
Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.
(c)
Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:
Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.