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Applicable linear expansion equation:
ΔL = αΔTL
In which
ΔL = change in length, α = Linear expansion coefficient of steel, ΔT = change in temperature, L = original length
Therefore,
ΔL = 12*10^-6*(18.5-(-3))*1410 = 0.36378 m
Answer:
638 m.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 94 m/s
Final velocity (v) = 22 m/s
Time (t) = 11 s
Distance (s) =?
We can obtain the distance travelled by using the following formula:
s = (u + v) t /2
s = (94 + 22) × 11 /2
s = 116 × 11 /2
s = 1276 /2
s = 638 m
Thus, the distance travelled is 638 m.
Their common speed is 1.53 m/s.
<h3>What is speed?</h3>
Speed can be defined as the ratio of the distance to the time of a body in motion.
To calculate their final speed, we use the formula below.
Formula:
- mu+m'u' = V(m+m')............. Equation 1
Where:
- m = mass of the Lee
- m' = mass of Mat
- u = initial speed of Lee
- u' = initial speed of Mat
- V = Their common speed.
make V the subject of the equation
- V = (mu+m'u')/(m+m')........... Equation 2
From the question,
Given:
- m = 40 kg
- m' = 80 kg
- u = 4.6 m/s
- u' = 0 m/s
Substitute these values into equation 2
- V = [(40×4.6)+(80×0)]/(40+80)
- V = 184/120
- V = 1.53 m/s.
Hence, Their common speed is 1.53 m/s.
Learn more about speed here: brainly.com/question/3004254