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scoundrel [369]

2 years ago

7

Why do we crack molecules?

2 answers:

olga2289 [7]2 years ago

5 0

Cracking is the process whereby complex organic molecules such as kerogens or long chain hydrocarbons are broken down into simpler molecules such as light hydrocarbons,.
it is done to get more important substances

tino4ka555 [31]2 years ago

4 0

We need to crack molecules in order for us to get the desired molecule. For example, in the extraction of crude oil, after entering the fractional distillation, it will give products base on their molecular structure. The products are gasoline, diesel fuel, jet fuel, wax, asbestos,kerosene.

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What is the electron configuration for ground-state Boron

hoa [83]

Answer:

The remaining electron will go in the 2p orbital. Therefore the B electron configuration will be 1s22s22p1.

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2 years ago

How many atoms are in 3 moles of carbon?

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18.06 x 10^23

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2 years ago

Read 2 more answers

A bicycle tire is filled with air to a pressure of 100. psi at a temperature of 19C. Riding the bike on asphalt on a hot day inc

Zigmanuir [339]

Considering the direct relationship between pressure and temperature, the new pressure in the bicycle tire would be 63.01 psi

<h3>Gas law</h3>

The general gas laws is given by:

P1V1/T1 = P2V2/T2

Where P1 = initial pressure V1 = initial volume T1 = initial temperature, P2 = final pressure, V2 = final volume, and T2 = final temperature.

In this case, P1 = 100 psi, V1 = 1, T1 = 19+273 = 292, P2 = ?, V2 = 1.4, T2 = 58+273 = 331

P2 = P1V1T2/T1V2

= 100x1x292/331x1.4

= 63.01 psi

More on gas laws can be found here: brainly.com/question/1190311

5 0

1 year ago

A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at

weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of tin = $m_1=18.5 g$

Specific heat capacity of tin = $c_1=0.21 J/g^oC$

Initial temperature of the tin = $T_1=97.38^oC$

Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=75.7 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=21.52^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)$

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

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3 years ago

Bonds payable issued with collateral are called _______ bonds.

NeX [460]

The answer to your question is letter D. Secured.

8 0

2 years ago