The first thing to is factor the denominator of the rational function:
to do this we'll need to find two number whose product is -3 and its sum is -2; those numbers are 1 and -3, so:
Now we can rewrite our rational function as follows:
Notice that we have a common factor (x-3) in both numerator and denominator; therefore we can cancel them:
Taking all the above into consideration we realize that x=3 is a removable discontinuity; the correct answer is the first one: there is a hole in x=3 and asymptote at x=-1.
Answer:
-(3x^2 + 16x + 5)
-(3x+1)(x+5)
Step-by-step explanation:
-1(3x^2+15x+x+5)
-1(3x^2+16x+5)
-3x^2-16x-5
Answer:the answer is A
Step-by-step explanation:
I know because i took the quiz and got it right
A function for which every element of the range of the function corresponds to exactly one element of the domain. One-to-one is often written 1-1. Note: y = f(x) is a function if it passes the vertical line test.
H= -1
Distribute:
-(4+h)= -4 - h
-4 - h= 3h
-4 +h = 3h + h
-4= 4h
-1 = h