Answer:
1/81
Step-by-step explanation:
Answer: what the heck do you have to answer
Step-by-step explanation:
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
Hello :
<span>the y-intercept of y = -4/3x + 4 when x=0 : y= (-4/3)(0)+4=4
Answer : </span><span>A) (0, 4)</span>
Answer:
sin α =
Step-by-step explanation:
sin α = 
= 
=
