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2 years ago

Can anybody help me plz

Mathematics

2 answers:

klio [65]2 years ago

6 0

Circumference formula is C=2 x 3.14 x radius

Radius in this case is 5 because it’s half of 10.
Multiply it all together and you should get C= 31.4

Alja [10]2 years ago

4 0

You do 3.14×diameter... the diameter in this case is 10

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What equation represents the relationship between p and q shown in the table

mash [69]

q = 10p because all of them are multiplied by ten

6 0

2 years ago

Which point is an intercept of the quadratic function

Oxana [17]

Answer:

x=15

Step-by-step explanation:

you get everything out of the parentheses then u subtract or add the two constants together which will give u 15

7 0

2 years ago

The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c

Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so $p = \frac{2}{20} = 0.1$ .

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487$

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0

2 years ago

Can someone please help me find the side length area, and please draw the shape on how it would look if it were finished

Mumz [18]

The side length is 5 units, and the area is 25 square units

<h3>What are areas?</h3>

The area of a shape is the amount of space it occupies

<h3>What is the area of a square</h3>

The area of a square is the product of its dimensions

From the graph, the coordinates of the square can be assumed to be:

$A = (0,0)$

$B = (4,3)$

The side length of the square is then calculated using the following distance formula

$d = \sqrt{(x_2- x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$AB = \sqrt{(0 - 4)^2 + (0-3)^2}$

$AB = \sqrt{25}$

$AB = 5$

The area of the square is the calculated as:

$Area = AB^2$

This gives

$Area = 5^2$

$Area = 25$

Hence, the side length is 5 units, and the area is 25 square units

See attachment for the diagram of the shape

Read more about areas at:

brainly.com/question/24487155

6 0

2 years ago

A package of paper weighs 3\frac{4}{6} ounces. If Edward put 3\frac{1}{2} packages of paper on a scale, how much would they weig

Nadusha1986 [10]

Answer:

They would weight $1\frac{1}{21}$ ounces

Step-by-step explanation:

Weight of complete package of paper = $3 \frac{4}{6}$ ounces

Weight of complete package of paper = $\frac{22}{6}$ ounces

Edward put $3\frac{1}{2}$ packages of paper on a scale

So, Weight of $3\frac{1}{2}$ packages $= \frac{\frac{22}{6}}{3\frac{1}{2}}$

Weight of $3\frac{1}{2}$ packages $= \frac{\frac{22}{6}}{\frac{7}{2}}$

Weight of $3\frac{1}{2}$ packages = $\frac{22}{21}=1\frac{1}{21}$

Hence They would weight $1\frac{1}{21}$ ounces

8 0

2 years ago