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2 years ago

5

I believe the answer is B but I think im wrong

1 answer:

brilliants [131]2 years ago

4 0

The second one is the correct answer. Plug in -3 into the equation.

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a stadium shaped like a hemisphere with a radius of 150 feet. last month the owners of the stadium paid $0.05 per cubic foot to

lesantik [10]

The formula for volume of a hemisphere is: V = 2/3 * π * r³

Volume = 2/3 x 3.14 x 150^3

Volume = 7,065,000 cubic feet.

Multiply the cost per cubic foot by the volume:

7,065,000 x 0.05 = 353,250

The total cost was $353,250

6 0

2 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

2 years ago

What is 3.1 × 2.57? (6-6)<br> A 8.432<br> B 7.967<br> C 6.621<br> D 5

Contact [7]

Answer:

B. 7.967

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the greatest factor of -2x?

Sveta_85 [38]

Answer:

this is prime

Step-by-step explanation:

3 0

2 years ago

is anyone willing to tutor me for free? I probably will just need help for a short bit because school is ending pretty soon and

dybincka [34]

Answer:

What math do you need help on?

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers