The earth's magnetic field is associated with the <span>core.</span>
Explanation:
It is given that,
Mass of the woman, m₁ = 52 kg
Angular velocity,
Mass of disk, m₂ = 118 kg
Radius of the disk, r = 3.9 m
The moment of inertia of woman which is standing at the rim of a large disk is :
I₁ = 790.92 kg-m²
The moment of inertia of of the disk about an axis through its center is given by :
I₂ =897.39 kg-m²
Total moment of inertia of the system is given by :
I = 1688.31 kg-m²
The angular momentum of the system is :
So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.
X=Ft is a possible equation for X because by using SI units its final term became Kg metre per second
Answer:
14.49 g/cm²
Explanation:
I = Io e^-(ux)
Where:
I = 573
Io = 1045
x = 0.3 inches and
rho = 11.4g/cm^3
Using the conversion constant
1 inch = 2.54 cm;
0.3 inches = 0.3 * 2.54 cm
0.3 inches = 0.762 cm
I/Io = e^-(ux), or say
Io/I = e^(ux), taking the In of both sides
ln(Io/I) = ux, making u subject of formula
u = 1/x * ln(Io/I)
u = 1/0.762 * ln(1045/573)
u = 1.312 * 0.6
u = 0.787
Next, we say that
u/rho = 0.7872/11.4 = 0.069
And finally, we make
1/(u/rho) to be our final answer
Inverse of the answer is = 14.49 g/cm²
Therefore, the um^-1 in g/cm^2? is 14.49