Answer:
5 x^2 y^ (-3) z = ?
Step-by-step explanation:
We know the volume of a rectangular prism is given by
V = l*w*h
V = 2x^2 * y^-2 * ?
We are given the volume
V =10x^4 y^-5 z
Set the two equal
10x^4 y^-5 z = 2x^2 * y^-2 * ?
Divide each side by 2x^2 y^-2
10x^4 y^-5 z /2x^2 y^-2 = 2x^2 * y^-2 * ?/2x^2 * y^-2
10x^4 y^-5 z/ 2x^2 y^-2 = ?
Simplifying
10/2 * x^4/x^2 y^-5/ y^-2 z = ?
We know that a^b/ a^c = a^(b-c)
5 x^ (4-2) y^(-5 - -2) z = ?
5 x^2 y^ (-5 +2) z = ?
5 x^2 y^ (-3) z = ?