Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
B.The exponent of the solution is –12, the difference of the original exponents.
C.The coefficient of the solution must be greater than or equal to one but less than 10.
D.The quotient is 3.0 ×
Step-by-step explanation:
Answer:
Heres how you do it
Step-by-step explanation:
10+2 =12 which means 72
Answer:
A. Matrix A
Step-by-step explanation:
When you put a systems of linear equations in matrix form, you take only the coefficients of the <em>xy </em>terms and sort them. <em>x</em> goes first, <em>y</em> comes after, and the numbers after the bars are the constants.
