Answer:
Option a) 50% of output expected to be less than or equal to the mean.
Step-by-step explanation:
We are given the following in the question:
The output of a process is stable and normally distributed.
Mean = 23.5
We have to find the percentage of output expected to be less than or equal to the mean.
Mean of a normal distribution.
- The mean of normal distribution divides the data into exactly two equal parts.
- 50% of data lies to the right of the mean.
- 50% of data lies to the right of the mean
Thus, by property of normal distribution 50% of output expected to be less than or equal to the mean.
Simple proportions.
You want a 1:5 ratio.
You have a 5:1 ratio.
So you add another 24 drops of white.
5:25 = 1:5
or
5/x = 1/5 and cross multiply.
Okie p utcpc gu puugkuxutupxpxuxuoxouuxuoxtxtpxotuxgxpxigxpccoucutxxpixditxgixcgcgicgicipcgicic
Well, if 6/4 equals 1.5 --
Then 1.5*5, (which is the next quantity of days before it hits 9) equals 7.5.
Hope this helps.
Answer:
see attached
Step-by-step explanation:
The equation is in the form ...
4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance
Comparing this to your equation, we see ...
p = 4, (h, k) = (3, 4)
p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...
vertex: (3, 4)
axis of symmetry: x = 3
focus: (3, 8) . . . . . 4 units up from vertex
directrix: y = 0 . . . horizontal line 4 units down from vertex