Firstly, we have to find the mean. The mean is simply the average of the numbers, which we find by adding each number in the sequence and then dividing that result by the total amount of numbers.
<em>13.3 + 14.3 + 15.3 + 16.3 + 17.3 = 76.5</em>
<em>76.5 / 5 = 15.3
</em>Okay, so our average is 15.3.
<em>
Now, </em>we have to subtract the mean from each number and then square the result.
<em>(13.3 - 15.3)^2 = 4</em>
<em>(14.3 - 15.3)^2 = 1</em>
<em>(15.3 - 15.3)^2 = 0</em>
<em>(16.3 - 15.3)^2 = 1</em>
<em>(17.3 - 15.3)^2 = 4
</em>Now we have to find the mean of those numbers!
<em>
4 + 1 + 0 + 1 + 4 = 10
10 / 2 = 2
</em>Finally, we take the square root of that number and we have our standard deviation. =)<em>
</em>
Answer:
374
Step-by-step explanation:
A = l×w
A=17×22
A=374
Answer:
Tbh Idek what to tell you
Step-by-step explanation:
Answer: 16 double rooms and 10 single rooms were rented.
Step-by-step explanation:
Let x represent the number of double rooms that were rented.
Let y represent the number of single rooms that were rented.
The total number of rooms rented in a day is 26. It means that
x + y = 26
A motel rents double rooms at $34 per day and single rooms at $26 per day. If all the rooms that were rented for one day cost a total of $804, it means that
34x + 26y = 804 - - - - - - - - - - -1
Substituting x = 26 - y into equation 1, it becomes
34(26 - y) + 26y = 804
884 - 34y + 26y = 804
- 34y + 26y = 804 - 884
- 8y = - 80
y = - 80/ - 8 = 10
x = 26 - y = 26 - 10
x = 16
Answer:
B. Perimeter of a square and
C. Side length of a square
Step-by-step explanation:
if n= side length of square then
- Area of square is
- Perimeter of a square is 4×n
- diagonal length of a square is × n
Thus,
Perimeter of square can be expressed as
×diagonal length of a square
Side length of a square can be expressed as
×diagonal length of a square
but Area of square is
×n×diagonal length of a square
As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>