Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
Step-by-step explanation:
We can find the area by breaking this into two rectangles one 3 by 7 and the other 1 by 2. The area of any rectangle is xy where x and y are its dimensions
A=3(7)+1(2)
A=21+2
A=23 yd^2
Answer:
30
Step-by-step explanation:
80% of 30 is 24 (u can use a calculator if you would like to check the answer but it is 30)
Sarah because if you add up the one time registration fee and the amount per month for one month it would be less than Joe's
<span>The answer would be (f(x) = (x – 8)2 – 56)</span>
