Answer:
21a^11b^3
Step-by-step explanation:
let me know if this is right
The 9 combinations that exist for two movements:
R,R
R,L
R,U *
L,R
L,L
L,U
U,R *
U,L
U,U
Walker would only be able to make it to (1,1) with only 2 of these combinations.
So if he were only allowed to make two movements, his chances of arriving at (1,1) would be 2/9.
Answer:
z=-2/3y+1
Step-by-step explanation:
Let's solve for z.
3yz+z=−2
Step 1: Factor out variable z.
z(3y+1)=−2
Step 2: Divide both sides by 3y+1.
z(3y+1)
3y+1
=
−2
3y+1
z=
−2
3y+1
Answer:
z=
−2
3y+1
Answer:
-2/4 or -0.5
Step-by-step explanation: