The answer is -93, here is the work :)
A guide wire for a palm tree makes a 32°angle with the ground and is staked 6 feet from the base of the tree. What is the length
, to the nearest tenth of a foot, of the guide wire from the ground to the palm tree? A. 7.1, B. 8.5, C. 9.6, D. 11.3
2 answers:
Answer:
Answer is 9.6
Step-by-step explanation:
From the illustration above. See attachment for interpretation of this illustration.
To find the part label a in the attachment which is the length of the foot of the guide wire from the ground to the palm tree, we apply the sine rule, which says
a/sineA = b/sineB
In this case
a = ? , A = 58° , b = 6ft, B = 32°
So
a/sine58 = 6/sine32
a/0.848 = 6/0.5299
a = 6*0.848/0.5299
a = 5.088/0.5299
a = 9.601 ~ 9.6
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Answer:
(0 , -1)
Step-by-step explanation:
WR = 4 + 2 = 6
WS = 1/3 x WR = 2 .... the point of 1:2 of WR
S (-2 + 2 , -4) i.e. (0,4)
The same reason: RQ = 1/3 x RY = 1/3 x (5 + 4) = 3
Q (-4 , -4 + 3) i.e. (-4, -1)
QP // RW
p (0 , -1)
