Answer:
9x^2-3x+4
Step-by-step explanation:
(3x^2+2x^2-5x+7)+(4x^2+2x-3)
5x^2-5x+7+4x^2+2x-3
5x^2+4x^2-5x+2x+7-3
9x^2-3x+7-3
9x^2-3x+4
Assuming the typewriter-looking words are the line names...
1. Line R
2. Line Q (Or R, but it is most likely Q)
3. Points E and F
Collinear Meaning: http://mathworld.wolfram.com/Collinear.html
Answer:
The distribution with n = 225 will give a smaller standard error.
Since sigma x = sigma/√n, dividing by the square root of 225 will result in a small standard error regardless of the value of sigma.
Step-by-step explanation:
Standard error is given by standard deviation (sigma) divided by square root of sample size (√n).
The distribution with n = 225 would give a smaller standard error because the square root of 225 is 15. The inverse of 15 multiplied by sigma is approximately 0.07sigma which is smaller compared to the distribution n = 100. Square of 100 is 10, inverse of 10 multiplied by sigma is 0.1sigma.
0.07sigma is smaller than 0.1sigma
<span>v = 45 km/hr
u = 72 km/hr
Can't sketch the graph, but can describe it.
The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are
1. A segment from (0,0) to (80,60)
2. A segment from (80,60) to (110,60)
3. A segment from (110,60) to (160,120)
The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed.
120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr
After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that.
45 * 4/3 = 180/3 = 60 km.
So we have a good cross check that our initial speed was correct. v = 45 km/hr
Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time:
60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr
So the 2nd leg of the trip was at a speed of 72 km/hr</span>
