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2 years ago

PLEASEEEEEEEEEEEE cries

Mathematics

1 answer:

Verizon [17]2 years ago

7 0

Answer:

D) a: 4(4) + 1/2(3)(4)

Step-by-step explanation:

1. The floor is split into a square and a triangle, as the two side lengths of the quadrilateral are both 4 feet.

C and D are looking for the area of a rectangle and a triangle. They can not be right.

2. The area of a triangle is found by multiplying the base and the height, which in this case, since it is a right triangle, the two legs. In that situation, said legs are 7 - 4 = 3 feet and 4 feet, while the hypotenuse is 5 ft. B plugs in the equation leg * hypotenuse, which is not correct.

The only answer is A (which is D in the selection).

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Cole wants to buy carpet to cover his whole living room, except for the tiled floor. The tiled floor is 4 5 6 ft by 2 1 3 ft. Fi

Shtirlitz [24]

Answer:

$Area = 49\frac{25}{36}$

Step-by-step explanation:

Given

Tile

$Length = 4\frac{5}{6}$

$Width = 2\frac{1}{3}$

See attachment for dimension of the floor

Required

Determine the area covered by the carpet

From the attachment, the dimension of the floor is:

$Length = 12\frac{1}{4}$

$Width = 5$

Calculate Area

$Area = Length * Width$

$Area = 12\frac{1}{4} * 5$

$Area = 61\frac{1}{4}$

The area of the tiles is:

$Area = 4\frac{5}{6} * 2\frac{1}{3}$

$Area = \frac{29}{6} * \frac{7}{3}$

$Area = \frac{203}{18}$

$Area = 11\frac{5}{18}$

So, the carpet area is:

$Area = Floor\ Area - Tile\ Area$

$Area = 61\frac{1}{4} - 11\frac{5}{18}$

To improper number

$Area = \frac{245}{4} - \frac{208}{18}$

Take LCM

$Area = \frac{2205 - 416}{36}$

$Area = \frac{1789}{36}$

$Area = 49\frac{25}{36}$

7 0

2 years ago

earnstyle [38]

Answer:

A, B, C

Step-by-step explanation:

whole number: the set of counting numbers, 1, 2, 3, ..., and includes the number 0.

integer: all whole numbers, zero, and all the negatives of the whole numbers: ..., -3, -2, -1, 0, 1, 2, 3, ...

rational: any number that can be written as a fraction of integers

irrational number: a number that cannot be written as a fraction of integers

1.00 is the same as 1

It is:

A whole number

B integer

C rational

6 0

2 years ago

Read 2 more answers

The credit department of Lion's Department Store in Anaheim, California, reported that 30% of their sales are cash, 30% are paid

Oliga [24]

Answer:

Hence the probability that she paid cash is 0.105

Step-by-step explanation:

P(cash) = 0.3

P(credit card ) = 0.3

P(debit card ) = 0.4

P ( more than $50 | cash ) = 0.2

P (more than $50 | credit card ) =0.9

P (more than $ 50 |debit card ) = 0.6

P ( more than $50) = P ( more than $50 | cash )* P (cash) + P (more than $50 credit card ) * P(credit card ) + P (more than $ 50 |debit card )* P(debit card )

= 0.2 * 0.3 + 0.9 * 0.3 + 0.6* 0.4

= 0.57

P ( more than $50) = P ( more than $50 | cash )* P (cash) / P ( more than $50)

= 0.2* 0.3 / 0.57

= 0.105

6 0

2 years ago

Anybody got some answers?

kiruha [24]

I don’t know if this is right but this is what I figured.
37.245508982

4 0

2 years ago

Suppose <img src="https://tex.z-dn.net/?f=m" id="TexFormula1" title="m" alt="m" align="absmiddle" class="latex-formula"> men and

ollegr [7]

Firstly, we'll fix the postions where the $n$ women will be. We have $n!$ forms to do that. So, we'll obtain a row like:

$\underbrace{\underline{~~~}}_{x_2}W_2 \underbrace{\underline{~~~}}_{x_3}W_3 \underbrace{\underline{~~~}}_{x_4}... \underbrace{\underline{~~~}}_{x_n}W_n \underbrace{\underline{~~~}}_{x_{n+1}}$

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

$x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m~~~(i)$

Since there is no women sitting together, we must write that $x_2,x_3,...,x_{n-1},x_n\ge1$ . It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

$\begin{cases}x_2=x_2'+1\\x_3=x_3'+1\\...\\x_{n-1}=x_{n-1}'+1\\x_n=x_n'+1\end{cases}$

The equation (i) can be rewritten as:

$x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m\\\\
x_1+(x_2'+1)+(x_3'+1)+...+(x_{n-1}'+1)+x_n+x_{n+1}=m\\\\
x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-(n-1)\\\\
x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-n+1~~~(ii)$

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: $\dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}$

[I can write the proof if you want]

Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: $m!$

Multiplying all results:

$n!\times\dfrac{(m+1)!}{n!(m-n+1)!}\times m!\\\\
\boxed{\boxed{\dfrac{m!(m+1)!}{(m-n+1)!}}}$

4 0

2 years ago

PLEASEEEEEEEEEEEE *cries*

PLEASEEEEEEEEEEEE cries