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2 years ago

The glow emitted by a substance exposed to eternal radiation is called

1 answer:

3 0

The glow emitted by a substance exposed to external radiation is called 'fluorescence'. In fluorescence, a fluorophore is exposed to external radiation, absorbs the energy and emits a form of light or glow. The answer to this question is 'fluorescence'. I hope this helps.

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Fe(NO3)2 not sure how to get the oxidation numbers of all elements

Shtirlitz [24]

You must remember that oxidation number of hydrogen in acids is always +1, oxidation number of oxygen in oxides & acids is always -2... metals has always oxidation number on plus!

group NO3 comes from HNO3...and oxidation number of whole acid group is always on minus and equal to the amount of hydrogen atoms in this acid... so oxidation number of NO3 = -1

we have 2 NO3 groups so 2*(-1) = -2 and that is the reason why oxidation number of Fe in this formula must be +2... because sum of all elements always gives 0!

Now we could count of oxidation number for nitrogen... we write HNO3 and start counting from right to left:
3*(-2) from oxygens + 1 from hydrogen = -5
so nitrogen must have +5 oxidation number... because sum all in formula must be 0.

4 0

2 years ago

Adding O2 to the reaction 6CO2 + 6H2O <---> C6H12O6 + 6O2, WHICH WAY WILL THE REACTION SHIFT?

Alex73 [517]

Increase in Oxygen shift the equilibrium towards reactant side.

<u>Explanation:</u>

6CO₂ + 6H₂O ⇄ C₆H₁₂O₆ + 6O₂

This is the reaction occurs in the photosynthesis of plants by means of sunlight. In this case, if the concentration of Oxygen increases or adding more oxygen to the product side will shift the equilibrium towards the reactant side according to the Le Chatlier's principle, which adjusts the equilibrium by itself for any changes that is increase or decrease in pressure, temperature or concentration of reactants or products.

5 0

2 years ago

As the temperature of a gas in a closed container increases, what is true of the particles in the substance? (2 points)

Misha Larkins [42]

The rate of movement increases, as they get faster with more energy.

8 0

2 years ago

Read 2 more answers

Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)

kolbaska11 [484]

Answer:

The amount of NaOH required to prepare a solution of 2.5N NaOH.

The molecular mass of NaOH is 40.0g/mol.

Explanation:

Since,

NaOH has only one replaceable -OH group.

So, its acidity is one.

Hence,

The molecular mass of NaOH =its equivalent mass

Normality formula can be written as: $Normality=\frac{mass of solute NaOH}{its equivalent mass} * \frac{1}{volume of solution in L} \\$

Substitute the given values in this formula to get the mass of NaOH required.

$2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\ = 100.0g$

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

8 0

2 years ago

A rule of thumb in baking is that 1/2 teaspoon of baking soda is neutralized by one cup of sour milk. the acid component in sour

Sophie [7]

Answer : The ionic equation will be:

$CH_3CH(OH)COO^-(aq)+H^+(aq)+Na^+(aq)+HCO_3^-(aq)\rightarrow CH_3CH(OH)COO^-(aq)+Na^+(aq)+H_2O(l)+CO_2(g)$

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid react with a base to give salt and water as a product that means it reacts to give a neutral solution.

When baking soda (sodium hydrogen carbonate) base react with lactic acid then it react to gives sodium lactate, carbon dioxide and water as a product.

The balanced chemical reaction will be:

$CH_3CH(OH)COOH(aq)+NaHCO_3(aq)\rightarrow CH_3CH(OH)COONa(aq)+H_2O(l)+CO_2(g)$

The ionic equation will be:

$CH_3CH(OH)COO^-(aq)+H^+(aq)+Na^+(aq)+HCO_3^-(aq)\rightarrow CH_3CH(OH)COO^-(aq)+Na^+(aq)+H_2O(l)+CO_2(g)$

3 0

2 years ago