How many solutions are there to this equation 3x(x-4)+5-x=2x-7
1 answer:
Answer:
2 solutions
Step-by-step explanation:
I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...
- x = 1
- x = 4
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To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:
3x(x -4) +5 -x -(2x -7) = 0
3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses
3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms
3(x -1)(x -4) = 0 . . . . . . . . . . . . . . . factor
The values of x that make these factors zero are x=1 and x=4. These are the solutions to the equation. There are two solutions.
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<em>Alternate method</em>
Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...
d = b^2 -4ac . . . . where a, b, c are the coefficients in the form ax^2+bx+c
d = (-15)^2 -4(3)(12) = 225 -144 = 81
This positive value means the equation has 2 real solutions.
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Answer:
length = x+6
width = x-6
Step-by-step explanation:
The area of rectangle is:
where A is area, l is length and w is width.
We know the area of this rectangle or table since we are given A = x^2-36.
First, substitute A = x^2-36 in.
Then we factor x^2-36, use the difference of two squares:
Compare the terms.
First, we have to understand that length is always longer or greater or have more values than width.
Hence length cannot be x-6 and width cannot be x+6 either.
Thus: