Answer:
The statement is false.
Step-by-step explanation:
A parallelogram is a figure of four sides, such that opposite sides are parallel
A rectangle is a four-sided figure such that all internal angles are 90°
Here, the statement is:
"A rectangle is sometimes a parallelogram but a parallelogram is always a
rectangle."
Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.
The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.
The correct statement would be:
"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"
<h2>
Answer:</h2>
<h3>True</h3>
<h2>
Step-by-step explanation:</h2>
<h3>Intrusive rocks, have large crystals that are usually visible without a microscope. </h3>
<h2>Therefore it's true. </h2>
<h2>Hope it help you </h2>
Answer:
gnrg
Step-by-step explanation:
Let the number be n. Then 2(n-10) = 6n + 14.
Multiplying out the left side, 2n - 20 = 6n + 14. Thus, -34=4n, and n = -17/2.
There are 6720 ways by 8 distinguishable books be placed in 5 shelves.
According to statement
The number of books (n) is 8
The number of shelves (r) is 5
Now, we find the ways by which the 8 books be placed in 5 distinguishable shelves
From Permutation formula
P(n,r) = n! / (n-r)!
Substitute the values then
P(n,r) = 8! / (8-5)!
P(n,r) = (8*7*6*5*4*3*2*1) / (3*2*1)
P(n,r) = 8*7*6*5*4
P(n,r) = 6720
So, there are 6720 ways by 8 distinguishable books be placed in 5 shelves.
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